Which of the following code displays the area of a circle if the radius is positive. a. if (radius! = 0) System. out. println (radius * radius * 3.14159); b. if (radius > = 0) System. out. println (radius * radius * 3.14159); c. if (radius 0) System. out. println (radius * radius * 3.14159);

Question

Computers and Technology

Miles Cochran

25 February, 14:13

Which of the following code displays the area of a circle if the radius is positive. a. if (radius! = 0) System. out. println (radius * radius * 3.14159); b. if (radius > = 0) System. out. println (radius * radius * 3.14159); c. if (radius 0) System. out. println (radius * radius * 3.14159);

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Answers (1)

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Reyna Sloan · Answer 1

d. if (radius > 0) System. out. println (radius * radius * 3.14159);

Explanation:

The positive values are those values that are greater than 0 (zero).0 is considered to be nonnegative number it is neither positive nor negative and for a zero radius the area will be 0. As we know the are of the circle is π*radius*radius, and π is 3.14159. So the correct answer matching to this condition is option d.

Which checks if the radius is greater than 0 then find the radius and print it.