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10 May, 22:37

A lever has an effort arm that is 8 meters long and the resistance arm that is 1.5 meters long, how much effort is needed to lift a 200 newton weight?

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Answers (2)
  1. 10 May, 23:28
    0
    37.5N of effort is needed

    Explanation:

    Assuming efficiency of the machine is 100%

    Efficiency = Work done by the load/Work done by the effort * 100%

    100% = Work done by the load/Work done by the effort * 100%

    1 = Work done by the load/Work done by the effort

    Cross multiplying,

    Work done by effort = Work done by Load

    Note that work done = Force * distance

    Work done by load = Weight * resistance arm

    = 200*1.5

    = 300Nm ... 1

    Work done by effort = Effort * effort arm

    = 8 * Effort ... 2

    Equating 1 and 2, we have;

    300 = 8*Effort

    Effort = 300/8

    Effort = 37.5N
  2. 11 May, 01:33
    0
    37.5N

    Explanation:

    Step 1:

    Data obtained from the question.

    Effort arm length = 8m

    Resistance arm length = 1.5m

    Effort force =.?

    Resistance force = 200N

    Step 2:

    Determination of the effort required to lift the 200N weight.

    The effort required can be achieved by applying the following equation:

    Effort force x Effort arm length = Resistance force x Resistance arm length

    Effort force x 8 = 200 x 1.5

    Divide both side by 8

    Effort force = (200 x 1.5) / 8

    Effort force = 37.5N

    Therefore, an effort of 37.5N is required to lift the 200N weight
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