Question 1 of 2. Count Frequency: [50 marks] Write a function that counts the frequencies of array elements. Your program will take an array as input from the user. Write a function called CountFreq ( ...) that takes the array as a parameter and print all elements and their frequencies. You can print the elements in any order.

The solution (Java programming Language) is given in the explanation section

Pay attention to comments for explanation

Explanation:

import java. util. Scanner;

public class num2 {

public static void main (String[] args) {

//Calling the CountFreq in the main method

CountFreq ();

}

//Defining the CountFreq Method

public static void CountFreq () {

Scanner in = new Scanner (System. in);

System. out. println ("Enter array size");

int arrSize = in. nextInt ();

//Creating the array

int [] arr = new int[arrSize];

//Creating another array to hold number frequencies

int [] freqArray = new int[arr. length];

//For counting occurence of a the same number

int count;

//Receiving the elements of the array

System. out. println ("Enter array Elements: ");

for (int i=0; i
{

System. out. println ("Enter the values");

arr[i] = in. nextInt ();

System. out. printf ("%d", arr[i]);

//Intialize frequency to - 1

freqArray[i] = - 1;

}

//Checking for occurence of numbers, Increasing the count variable

//Avoiding duplicates

for (int i=0; i
{

count = 1;

for (int j=i+1; j
{

//Check for duplicate

if (arr[i]==arr[j])

{

count++;

/ / Avoid counting same element twice

freqArray[j] = 0;

}

}

//If frequency of current element is not counted

if (freqArray[i]! = 0)

{

freqArray[i] = count;

}

}

//Output of frequencies

System. out. println ("Frequency of all elements of array");

for (int i=0; i
{

if (freqArray[i]! = 0)

{

System. out. printf ("%d occurs %d times/n", arr[i], freqArray[i]);

}

}

}

}