Mix 'em Let s1 and s2 be 2 c-strings of the same length. Write a function char * mixem (chars1, char s2) which returns a c-string made up of the characters of s1 and s2 "interleaved", starting with the first character of s1. Example: S1="abc", s2="123" The call mixem (s1, s2) returns the c-string "a1b2c3" Note: If s is a c-string, strlen (s) returns the length of the string (not counting the terminating null character '/0'.) Every c-string has a null character at the end.

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Computers and Technology

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29 December, 04:05

Mix 'em Let s1 and s2 be 2 c-strings of the same length. Write a function char * mixem (chars1, char s2) which returns a c-string made up of the characters of s1 and s2 "interleaved", starting with the first character of s1. Example: S1="abc", s2="123" The call mixem (s1, s2) returns the c-string "a1b2c3" Note: If s is a c-string, strlen (s) returns the length of the string (not counting the terminating null character '/0'.) Every c-string has a null character at the end.

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Yair Fowler · Answer 1

See Explaination

Explanation:

#include

#include

using namespace std;

char * mixem (char * s1, char * s2);

int main () {

cout << mixem ("abc", "123") << endl;

cout << mixem ("def", "456") << endl;

return 0;

}

char * mixem (char * s1, char * s2) {

char * result = new char[1 + strlen (s1) + strlen (s2) ];

char * p1 = s1;

char * p2 = s2;

char * p = result;

while (*p1 || * p2) {

if (*p1) {

*p = * p1;

p1++;

p++;

}

if (*p2) {

*p = * p2;

p2++;

p++;

}

}

*p = '/0';

return result;

}