Consider the following program where the zu format specifier is used to display as an integer the result of sizeof. #include #include typedef union { int * i1; int * i2; }U; int main () { U temp; int i = 50; temp. i1 = &i; printf ("%zu and %d/n", sizeof (temp), * (temp. i2)); return 0; } What is the output of the program above? Note in the choices below indicates output that isn't any of the literal values in the code above.

Question

Computers and Technology

Kendall Humphrey

30 May, 10:01

Consider the following program where the zu format specifier is used to display as an integer the result of sizeof. #include #include typedef union { int * i1; int * i2; }U; int main () { U temp; int i = 50; temp. i1 = &i; printf ("%zu and %d/n", sizeof (temp), * (temp. i2)); return 0; } What is the output of the program above? Note in the choices below indicates output that isn't any of the literal values in the code above.

+3

Answers (1)

Know the Answer?

Claire Carney · Answer 1

4 and 50

Explanation:

To answer the question above, we are to first of all consider the size of union will be the max size of datatype in union data. I. E.

sizeof (int * ) is 4 bytes

so, sizeof (U) = sizeof (temp) is 4

and we saved 50 in temp. i1. so, 50 we can access 50 from temp. i2 as well

so, output is 4 and 50