The function prototype double mySqrt (int x); Declares a function called mySqrt which takes a double as an argument and returns an integer. Defines a function called mySqrt which takes an argument of type x and returns a double. Declares a function called mySqrt which takes an integer as an argument and returns a double. Defines a function called double which calculates square roots.

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Ashly Ochoa

5 February, 18:11

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Clinton Simon · Answer 1

A) declares a function called mySqrt that takes integer as argument and returns double.