Assume that the 100,000 element integer array that you allocated starts at address 0x50000000 in memory, the size of an integer is 4 bytes and the D-cache is initially empty. As you read the integers in the array one-by-one, starting at index 0, how many D-cache misses will you see for reading the first 40 integers when the cache block size is (to be answered without running pin) : a) 4 bytes:b) 32 bytes:c) 64 bytes:

40, 5 and 3

See explaination for the details

Explanation:

A)

Consider the data.

Assume D-cache is empty

An integer size = 4bytes

The cache block size = 4bytes

Therefore, the number of D-cache misses for reading the first 40 integers is,

= (40*4) / 4

= 160/4

= 40

b)

Consider the data.

Assume D-cache is empty

An integer size = 4bytes

The cache block size = 32bytes

Therefore, the number of D-cache misses for reading the first 40 integers is,

= (40*4) / 32

= 160/32

= 5

c)

Consider the data.

Assume D-cache is empty

An integer size = 4bytes

The cache block size = 64bytes

Therefore, the number of D-cache misses for reading the first 40 integers is,

= (40*4) / 64

= 160/64

= 3