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Computers and TechnologyComputers and Technology
3 March, 14:54

Given an ip address 172.16.28.252 with a subnet mask of 255.255.240.0, what is the correct network address?

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  1. 3 March, 16:39
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    172.16.16.0 is the network address.

    255.255.240.0 - > 8 bits (from last octet) + [ 255 - 240 = (15 = > 1 + 2 + 4 + 8) ] I'll take 4 bits "borrow" from third octet = have total 12 bits for hosts!

    Thus: 32 bits - 12 bits = / 20 VLSM with 4094 hosts can be subnetting in 16 subnets
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