According to information found in an old hydraulies book, the energy loss per unit weight of fluid flowing through a nozzle connected to a hose can be estimated by the formulah = (0.04 to 0.09) (D/d) ^4V^2/2g where h is the energy loss per unit weight, D the hose diameter, d the nozzle tip diameter, V the fluid velocity in the hose, and g the acceleration of gravity. do you think this equation is a valid in any system units? Explain.

Question

Engineering

Krish

5 July, 23:48

According to information found in an old hydraulies book, the energy loss per unit weight of fluid flowing through a nozzle connected to a hose can be estimated by the formulah = (0.04 to 0.09) (D/d) ^4V^2/2g where h is the energy loss per unit weight, D the hose diameter, d the nozzle tip diameter, V the fluid velocity in the hose, and g the acceleration of gravity. do you think this equation is a valid in any system units? Explain.

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Answers (1)

Know the Answer?

Benjamin Cohen · Answer 1

Yes equation is valid.

Explanation:

Given:

h = (0.04 to 0.09) (D/d) ^4*V^2/2*g

Using SI units to assign dimensions to every quantity as follows:

Energy loss per unit weight h = J / N = kg m ^2 s^-2 / kg m s^-2 = [m]

Hose diameter D = [m]

Nozzle tip diameter d = [m]

Fluid velocity in the hose V = [ m s^-1 ]

Acceleration of gravity g = [ m s^-2 ]

Using the Given Equation and plug the SI units of respective quantities:

h = (0.04 to 0.09) (D/d) ^4*V^2/2*g

[m] = (0.04 to 0.09) ([m] / [m]) ^4*[ m s^-1 ]^2/2*[ m s^-2 ]

Simplify the equation above:

[m] = (1) ^4 * [ m^2 s^-2 ] / [ m s^-2 ]

[m] = [m]

Hence, SI units of RHS of given equation = LHS of given equation, we can say the equation has consistent dimensions.