A house is losing heat at a rate of 1700 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Express the rate of heat loss from this house per K, °F, and R difference between the indoor and the outdoor temperature. The rate of heat loss from this house per K difference is kJ/h. The rate of heat loss from this house per °F difference is kJ/h. The rate of heat loss from this house per R difference is kJ/h.

Question

Engineering

Sonny

6 August, 21:23

A house is losing heat at a rate of 1700 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Express the rate of heat loss from this house per K, °F, and R difference between the indoor and the outdoor temperature. The rate of heat loss from this house per K difference is kJ/h. The rate of heat loss from this house per °F difference is kJ/h. The rate of heat loss from this house per R difference is kJ/h.

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Lucia · Answer 1

1700kJ/h. K

944.4kJ/h. R

944.4kJ/h.°F

Explanation:

Conversions for different temperature units are below:

1K = 1°C + 273K

1R = T (K) * 1.8

= (1°C + 273) * 1.8

1°F = (1°C * 1.8) + 32

Q/delta T = 1700kJ/h.°C

T (K) = 1700kJ/h.°C

= 1700kJ/K

T (R) = 1700kJ/h.°C

= 1700kJ/h.°C * 1°C/1.8R

= 944.4kJ/h. R

T (°F) = 1700kJ/h.°C

= 1700kJ/h.°C * 1°C/1.8°F

= 944.4kJ/h.°F

Note that arithmetic operations like subtraction and addition of values do not change or affect the value of a change in temperature (delta T) hence, the arithmetic operations are not reflected in the conversion. Illustration: 5°C - 3°C

= 2°C

(273+5) - (273+3)

= 2 K