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13 April, 21:17

Calculate the pressure drop in a duct (measured by a differential oil manometer) if the differential height between the two fluid columns is 3.2 cm and the density of oil is 860 kg/m3.

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  1. 14 April, 01:11
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    The pressure drop is 269.7N/m^2

    Explanation:

    ∆P = ∆h * rho * g

    ∆h = 3.2cm = 3.2/100 = 0.032m, rho = 860kg/m^3, g = 9.8m/s^2

    ∆P = 0.032*860*9.8 = 269.7N/m^2
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