Ask Question
18 October, 13:16

2. A sand core used to form the internal surfaces of a brass casting experiences a buoyancy force of 14 kg. The volume of the mold cavity forming the outside surface of the casting = 4500 cm3. What is the weight of the final casting? Ignore considerations of shrinkage. (Sand density = 1.6 g/cm3, brass casting density = 8.62 g/cm3).

+5
Answers (1)
  1. 18 October, 15:14
    0
    weight of final casting is 1134.4 kg

    Explanation:

    The formula for buoyancy force is;

    B=ρ*v*g where

    B=Buoyancy force in Newtons=140N

    ρ=density of sand = 1.6g/cm³=1600kg/m³

    v=volume of sand displaced

    g=acceleration due to gravity = 9.8 m/s²

    Applying the formula,

    140=1600*v*9.806

    140=15689.6v

    140/15689.6 = v

    0.008923 m³=v

    This the volume of the displaced body

    The volume of the mold cavity forming the outside surface of the casting = 4500 cm³ = 0.0045 m³

    Total volume will be : 0.008923 + 0.0045 = 0.01342 m³

    Formula for mass of brass = density of brass * total volume

    Mass of brass=8620 * 0.01342 = 115.7

    Weight of brass = mass of brass*acceleration due to gravity

    w=mg

    w=115.7*9.806 = 1134.4 kg
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “2. A sand core used to form the internal surfaces of a brass casting experiences a buoyancy force of 14 kg. The volume of the mold cavity ...” in 📘 Engineering if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers