A 1000-turn coil of wire 1.0 cm in diameter is in a magnetic field that increases from 0.10 T to 0.30 T in 10 ms. The axis of the coil is parallel to the field. What is the emf of the coil

emf generated by the coil is 1.57 V

Explanation:

Given details-

Number of turns of wire - 1000 turns

The diameter of the wire coil - 1 cm

Magnetic field (Initial) = 0.10 T

Magnetic Field (Final) = 0.30 T

Time=10 ms

The orientation of the axis of the coil = parallel to the field.

We know that EMF of the coil is mathematically represented as -

E=N (ΔФ/Δt)

Where E = emf generated

ΔФ = change inmagnetic flux

Δt = change in time

N = no of turns*area of the coil

Substituting the values of the above variables

=1000*3.14*0.5*10-4

=.0785

E=0.0785 (.2/10*10-3)

=1.57 V

Thus, the emf generated is 1.57 V