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1 December, 10:37

4. A 1 m3 rigid tank has propane at 100 kPa, 300 K and connected by a valve to another tank of 0.5 M3 with propane at 250 kPa, 400 K. The valve is opened and the two tanks come to a uniform state at 325 K. What is the final pressure?

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  1. 1 December, 14:02
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    139.97 kPa

    Explanation:

    Assuming propane is an ideal gas

    PV = nRT

    n₁ (number of mole f the first gas) of the 1 m³ rigid tank = P₁V₁ / RT₁ R gas constant = 8.314 J/mol

    n₁ = 100kPa * 1 m³ / (8.314 J/mol * 300 K) = 0.0401 mol

    n₂ = 0.5 m³ * 250 kPa / (8.314J/mol * 400 K) = 0.0376 mol where n₂ is the number of mole of the second gas

    n total = n₁ + n₂ = 0.0401 mol + 0.0376 mol = 0.0777 mol

    PV = nRT

    P final pressure = nRT / V where V = V₁ + V₂ = 1 m³ + 0.5 m³ = 1.5 m³

    P final pressure = 0.0777 mol * 8.314 J/mol * 325 K / 1.5 m³ = 139.97 kPa
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