For a 2 Vpp signal that fits within the ADC's input range, find the SQNR for: a) an 8-bit ADC with an input range of 1V to 6V b) a 9-bit ADC with an input range of 0V to 4V

SNR of ADC

If No of bit = n

So,

SNR = 20 log * rms Signal / rms Noise

SNR = 6.02n + 1.75 db

SNR only depends on No pf bit

A) No of bit (n) = 8

SNR = 6.02 * 8 + 1.75

SNR = 49.92db

Or

SNR = 50db

B) No of bit (n) = 9

SNR = 6.02 * 9 + 1.75

SNR = 55.94db

Or

SNR = 56db

If we increase a bit by one than SNR increase by 6db

If n (↑) by 1 bit SNR increase by 6db