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5 March, 01:07

If p is a pressure, V a velocity, and a fluid density, what are the dimensions (in the MLT system) of (a) p/, (b) pV, and (c) p/pV2?

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  1. 5 March, 01:14
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    Answer:p=ML^-1T^-2

    b) PV=MT^-3

    c) P/PV^2=T^2L^-2

    Explanation:In dimensions, Mass in kg is represented by M

    Length is represented by L in meters.

    T represent Time in seconds, s.

    Pressure=hpg, h=height or depth In m, a=density=kg/m^3

    g=acceleration due to gravity, m/s^2

    P=hag=mxkg/m^3 xm/s^2=m^2*kg/m^2*s^2=kgm^-1 s^-2=ML^-1T^-2

    B) PV=pressure xvelocity

    =ML^-1T^-2*distance/time

    ML^-1T^-2*L/T=MT^-3

    C) p/pv^2=1/V^2 = (time/distance) ^2 = (T/L) ^2=T^2L^-2
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