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25 March, 17:34

The mass fractions of total ferrite and total cementite in an iron-carbon alloy are 0.91 and 0.09, respectively. Is this a hypoeutectoid or hypereutectoid alloy? Why?

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  1. 25 March, 19:26
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    hypoeutectoid

    Explanation:

    ferrite: pure form of iron

    cementite: It is iron carbide with 93.3% iron and 6.67% carbon

    hypoeutectoid: Eutectoid steel with carbon fraction less than 0.8%

    hypereutectoid: Eutectoid Steel with carbon content more than 0.8%

    For the mentioned iron-carbide alloy,

    % of carbon in iron-carbide alloy = percentage of cementite * percentage of carbon in cementite

    % of carbon in iron-carbide alloy = 0.09 * 0.0667

    = 0.6%

    so the alloy is hypoeutectoid
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