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4 May, 01:19

A piston cylinder device contains 5 kg of Refrigerant 134a at 600 kPa and 80 C. The refrigerant is now cooled at constant pressure until it reaches a liquid-vapor mixture state with a quality of 0.3. How much heat was extracted in the process?

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  1. 4 May, 01:43
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    The answer is 920 kJ

    Explanation:

    Solution

    Given that:

    Mass = 5kg

    Pressure = 600 kPa

    Temperature = 80° C

    Liquid vapor mixture state (quality) = 0.3

    Now we find out the amount of heat extracted in the process

    Thus

    Properties of RI34a at:

    P₁ = 600 kPa

    T₁ = 80° C

    h₁ = 320 kJ/kg

    So,

    P₁ = P₂ = 600 kPa

    X₂ = 0.3

    h₂ = 136 kJ/kg

    Now

    The heat removed Q = m (h₁ - h₂)

    Q = 5 (320 - 136)

    Q = 5 (184)

    Q = 920 kJ

    Therefore the amount of heat extracted in the process is 920 kJ
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