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11 August, 18:36

If Qr = 4 C of charge moves to the right in tr = 4.0 s while Ql = - 1525 mC of charge moves to the left in t = 2.2 s, what is the net current to the right?

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  1. 11 August, 21:16
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    The answer to the question is

    The net current to the right = 1.639 A

    Explanation:

    Current flow direction is measured in terms of the direction of the positive charges, however the equivalent flow of negatively charge particles (electrons) in the opposite direction is called electric current flow

    Here the given variables are

    Qr = 4 C of charge migrate to the right

    tr = time of Qr migration to the right

    Ql = - 1525 mC charge migrate to the left

    tl = time of displacement of charge tl

    The unit of current is the Ampere A and 1 A = 1 C/s

    Therefore the current flow to the right is

    ir = dQr/dtr = (4 C) / (4.0 s) = 1 A

    The charge Ql = - 1525 mC = - 1.525 C moves the left, which is equivalent to current of the same magnitude to the right hence

    il = dQl/dtl = (-1.525 C) / (2.2 s) = - 0.693 A

    By the definition of current flow, the net current to the right = 1 A - (-0.693) = 1.639 A
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