The constant-pressure specific heat of air at 25°C is 1.005 kJ/kg·°C. Express this value in kJ/kg·K, J/g·°C, kcal / kg·°C, and Btu/lbm·°F. Round the final answers to three decimal place

a) C_v = 1.005 KJ/kgK

b) C_v = 1005.000 J/kgC

c) C_v = 0.240 kcal/kgC

d) C_v = 0.240 Btu/lbmF

Explanation:

Given:

- constant-pressure specific heat C_v = 1.005 KJ/kgC

Find C_v in units of:

a) kJ/kg·K

b) J/g·°C

c) kcal / kg·°C

d) Btu/lbm·°F

Solution:

a) C_v is Specific heat capacity is the quantity of heat needed to raise the temperature per unit mass. Usually, it's the heat in Joules needed to raise the temperature of 1 gram of sample 1 Kelvin or 1 degree Celsius. Hence,

C_v = 1.005 KJ/kgK

b)

C_v = 1.005 KJ/kgC * (1000 J / KJ)

C_v = 1005.000 J/kgC

c)

C_v = 1.005 KJ/kgC * (0.239006 kcal / KJ)

C_v = 0.240 kcal/kgC

d)

C_v = 1.005 KJ/kgC * (0.947817 Btu / KJ) * (kg / 2.205 lbm) * (Δ1 C / Δ1.8 F)

C_v = 0.240 Btu/lbmF