Nitrogen at an initial state of 300 K, 150 kPa and 0.2 m3is compressed slowly in an isothermal process to a final pressure of 800 kPa. Determine the work done to the nitrogen and the amount of heat transfer during this process.

-50.22kJ

Explanation:

Given:

Initial state Temperature = 300k

Pressure 1 = 150kPa

Pressure 2 = 800kPa

Volume 1 = 0.2m^3

Work done = Pressure 1 * Volume 1 * (inverse of pressure 1 : pressure 2)

= 150kPa * 0.2m^3 * (inv 150 kPa : 800 kPa)

= - 50.22kJ