Ask Question
17 August, 06:21

An air conditioner using refrigerant R-134a as the working fluid and operating on the ideal vapor-compression refrigeration cycle is to maintain a space at 22°C while operating its condenser at 1000 kPa.

a. Determine the COP of the system when a temperature difference of 2°C is allowed for the transfer of heat in the evaporator.

+3
Answers (1)
  1. 17 August, 09:25
    0
    COP=13.37

    Explanation:

    Considering the allowed temperature difference the temperature in the evaporator will be 20°. The enthalpy and entropy at this temperature are obtained from table for the saturated vapor phase:

    h_1=261.64 kJ/kg

    s_1=0.92254 kJ/kgK

    The enthalpy at state 2 is determined from the given condenser pressure and the condition s_2 = s_1 with data from table using interpolation:

    h_2=273.18 kJ/kg

    The enthalpy at states 3 and 4 is determined from the saturated liquid value for the condenser pressure from table:

    h_3=h_4=107.34 kJ/kg

    the COP is then:

    COP=qL/w

    = h_1 - h_4 / h_2 - h_1

    =13.37
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “An air conditioner using refrigerant R-134a as the working fluid and operating on the ideal vapor-compression refrigeration cycle is to ...” in 📘 Engineering if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers