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7 February, 14:40

A platinum resistance temperature sensor has a resistance of 120 Ω at 0℃ and forms one arm of a Wheatstone bridge. At this temperature the bridge is balanced with each of the other arms being 120 Ω. The temperature coefficient of resistance of the platinum is 0.0039/K. What will be the output voltage from the bridge for a change in temperature of 20℃? The loading across the output is effectively open circuit and the supply voltage to the bridge is from a source of 6.0 V with negligible internal resistance.

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  1. 7 February, 18:03
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    Answer : 9.36ohms / temperature

    Explanation:

    Expression for the variation of resistance of platinum with temperature

    Rt = Ro (1+*t)

    Rt = resistance @ t°C

    Ro = resistance @ 0°C

    * = temperature coefficient of resistance

    Calculate the change in resistance by putting 120ohms for Ro,

    0.0039/K for *

    20°C for t

    Using this formula:

    Rt = Ro (1+*t)

    Rt - Ro = Ro*t

    = (120ohms) (0.0039/K) (20°C)

    = 9.36ohms/K
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