Ask Question
8 March, 04:02

At 500oC, the diffusion coefficient of Cu in Ni is 1.3 x 10-22 m2/s, and the activation energy for diffusion is 256,000 J/mol. From this information, determine the diffusion coefficient of Cu in Ni at 900 oC. (R = 8.314 J / (mol K)) 0oC = 273 K

+1
Answers (1)
  1. 8 March, 06:39
    0
    the diffusion coefficient at 900°C is D₂=8.9*10⁻¹⁸ m²/s

    Explanation:

    The dependence of the diffusion coefficient is similar to the dependence of chemical reaction rate with respect to temperature, where

    D=D₀*e^ (-Q/RT)

    where

    D₀ = diffusion energy at T=∞

    Q = activation energy

    T = absolute temperature

    D = diffusion coefficient at temperature T

    R=ideal gas constant

    for temperatures T₁ and T₂

    D₁=D₀*e^ (-Q/RT₁)

    D₂=D₀*e^ (-Q/RT₂)

    dividing both equations and rearranging terms we get

    D₂=D₁*e^[-Q/R (1/T₂-1/T₁) ]

    replacing values

    D₂=D₁*e^[-Q/R (1/T₂-1/T₁) ] = 1.3*10⁻²² m²/s*e^ (-256,000 J/mol/8.314 J / (mol K) * (1/1073K-1/773K) = 8.9*10⁻¹⁸ m²/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “At 500oC, the diffusion coefficient of Cu in Ni is 1.3 x 10-22 m2/s, and the activation energy for diffusion is 256,000 J/mol. From this ...” in 📘 Engineering if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers