A waste treatment pond is 50m long and 25m wide, and has an average depth of 2m. The density of the waste is 75.3 lbm/ft3. Calculate the weight of the pond contents in lbf, using a single dimensional equation for your calculation.

Question

Engineering

Jaxon Schaefer

30 May, 13:20

A waste treatment pond is 50m long and 25m wide, and has an average depth of 2m. The density of the waste is 75.3 lbm/ft3. Calculate the weight of the pond contents in lbf, using a single dimensional equation for your calculation.

+2

Answers (1)

Know the Answer?

Blaze Ferguson · Answer 1

The weight of the pond contents is 6,643,233.22 lbf

Explanation:

Weight = density * volume * acceleration due to gravity

density = 75.3lbm/ft^3 = 75.3lbm/ft^3 * 0.45359kg/1lbm * (3.2808ft/1m) ^3 = 1206.14kg/m^3

volume = length*width*depth = 50m*25m*2m = 2500m^3

acceleration due to gravity = 9.8m/s^2

Weight = 1206.14*2500*9.8 = 29,550,430N = 29,550,430N * 1lbf/4.4482N = 6,643,233.22lbf