An axial compressive load of 708 kN is applied to a cylindrical component, 81 mm in diameter and 418 mm long, made of aluminium. Calculate the compressive stress, fc

The compressive stress of aplying a force of 708 kN in a 81 mm diamter cylindrical component is 0.137 kN/mm^2 or 137465051 Pa ( = 137.5 MPa)

Explanation:

The compressive stress in a cylindrical component can be calculated aby dividing the compressive force F to the cross sectional area A:

fc = F/A

If the stress is wanted in Pascals (Pa), F and A must be in Newtons and square meters respectively.

For acylindrical component the cross sectional area A is:

A=πR^

If the diameter of the component is 81 mm, the radius is the half:

R=81mm / 2 = 40.5 mm

Then A result:

A = 3.14 * (40.5 mm) ^2 = 5150.4 mm^2

In square meters:

A = 3.14 * (0.0405 m) ^2 = 0.005150 m^2

Replacing 708 kN to the force:

fc = 708 kN / 5150.4 mm^2 = 0.137 kN/mm^2

Using the force in Newtons:

F = 70800 N

Finally the compressive stress in Pa is:

fc = 708000 / 0.005150 m^2 = 137465051 Pa = 137 MPa