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9 October, 23:47

If a signal is transmitted at a power of 250 mWatts (mW) and the noise in the channel is 10 uWatts (uW), if the signal BW is 20MHz, what is the maximum capacity of the channel?

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  1. 10 October, 00:24
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    C = 292 Mbps

    Explanation:

    Given:

    - Signal Transmitted Power P = 250mW

    - The noise in channel N = 10 uW

    - The signal bandwidth W = 20 MHz

    Find:

    what is the maximum capacity of the channel?

    Solution:

    -The capacity of the channel is given by Shannon's Formula:

    C = W*log_2 (1 + P/N)

    - Plug the values in:

    C = (20*10^6) * log_2 (1 + 250*10^-3/10)

    C = (20*10^6) * log_2 (25001)

    C = (20*10^6) * 14.6096

    C = 292 Mbps
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