How much total heat energy input is needed to raise the temperature from 20°C to 100°C for 15-kg steel container filled with 17-kg liquid? [cst = 450 J/kg. Co and cli = 4100 J/kg. Co]

Total heat energy input needed is 6116kJ

Explanation:

This problem bothers heat capacity

Assuming that the steel container and the liquid have same temperatures

Given data

Initial temperature of liquid and steel container θ1=20°C

Final temperature of liquid and steel containers θ2 = 100°C

Mass of container M1 = 15kg

Mass of liquid M2 = 17kg

Specific heat capacity of steel container cst450 J/kg. C

Specific heat capacity of

Liquid cli = 4100 J/kg. C

We know that the heat applied is given as

Q = mcΔθ

Total heat applied = Ql + Qs

Where Ql = heat applied to liquid

Qs = heat applied to steel

Substituting our given data we have

Q = 15*450 (100-20) + 17*4100 (100-20)

Q = 6750 (80) + 69700 (80)

Q=540000+5576000

Q = 6116000

Q = 6116kJ