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16 April, 21:49

A 50 Ibm block is moving at 4 ft/s. Find Its total kinetic energy? Also find Its kinetic energy per unit mass is

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  1. 16 April, 22:46
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    Total kinetic energy = 400 puondal foot

    Kinetic energy per unit mass = 8 (poundaul foot/lb)

    Explanation:

    To determine the total kinetic energy of the block we use the equation:

    Kinetic energy = (1/2) * m * (v^{2}) = (1/2) * (50lb) * (4 foot/s) ^{2}) =

    = 400 poundal foot

    To establish the kinetic energy per unit of mass we must simply divide the value of the total kinetic energy obtained previously by the mass of the block obtaining:

    Kinetic energy per unit mass = (400 poundal foot) / (50lb) =

    = 8 (poundaul foot/lb)
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