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16 February, 20:57

Heat is transferred at a rate of 2 kW from a hot reservoir at 875 K to a cold reservoir at 300 K. Calculate the rate at which the entropy of the two reservoirs changes. (Round the final answer to six decimal places.) The rate at which the entropy of the two reservoirs changes is kW/K. Is the second law satisfied?

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  1. 16 February, 21:43
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    The correct answer is 0.004382 kW/K, the second law is a=satisfied and established because it is a positive value.

    Explanation:

    Solution

    From the question given we recall that,

    The transferred heat rate is = 2kW

    A reservoir cold at = 300K

    The next step is to find the rate at which the entropy of the two reservoirs changes is kW/K

    Given that:

    Δs = Q/T This is the entropy formula,

    Thus

    Δs₁ = 2 / 300 = 0.006667 kW/K

    Δs₂ = 2 / 875 = 0.002285

    Therefore,

    Δs = 0.006667 - 0.002285

    = 0.004382 kW/K

    Yes, the second law is satisfied, because it is seen as positive.
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