Ask Question
17 August, 08:51

If 20 kg of iron, initially at 12 °C, is added to 30 kg of water, initially at 90 °C, what would be the final temperature of the combined system? (Hint: the heat given up by the water will be equal to the heat gained by the iron) Explain how you would represent this problem in the simulation.

+1
Answers (1)
  1. 17 August, 09:26
    0
    final temperature of the combined system T = 84.78°C

    Explanation:

    Given data

    mass of iron (m1) = 20 kg

    temperature iron (t1) = 12 °C

    mass of water (m2) = 30 kg

    temperature of water (t2) = 90 °C

    To find out

    final temperature of the combined system

    solution

    we know the energy requirement formula to rise the temp

    energy = mass * specific heat * change in temperature

    we combine both system so both energy will be added

    and

    we know specific heat of iron (c1) = 0.450 kJ/kg

    and specific heat of water (c2) = 4.186 kJ/kg

    4.186 joule/gram °C

    now combine both energy

    energy = mass, m1 * specific heat, c1 * change in temperature, T - t1 + mass, 2 * specific heat, c2 * change in temperature, T - t2

    energy = 20 * 0.450 * T - 12 + 30 * 4.186 * T - 90

    (20) (0.45) (T-12) = (30) (4.186) (90-T)

    final temperature of the combined system T = 84.78°C
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If 20 kg of iron, initially at 12 °C, is added to 30 kg of water, initially at 90 °C, what would be the final temperature of the combined ...” in 📘 Engineering if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers