Ask Question
19 May, 04:06

Neglecting the presence of friction, air drag, and other inefficiencies, how much gasoline is consumed when a 1300 kg automobile accelerates from rest to 80 km/h. Assume the density and enthalpy of gasoline are 680 kg/m3 and 45 MJ/kg respectively. Express your answer in the units of mL. Show all work and use SI units for full credit. Box your final answer (s)

+4
Answers (1)
  1. 19 May, 07:55
    0
    Given that,.

    Mass of car is

    M = 1300kg

    Velocity of car

    V = 80km/h = 80 * 1000/3600

    V = 22.22m/s

    Calculate the kinetic energy of the vehicle as follows:

    K. E = ½ MV²

    K. E = ½ * 1300 * 22.22²

    K. E = 320,987.65 J

    Given that,

    Enthalpy is 45MJ / kg

    h = 45MJ / kg

    Then, enthalpy is given as.

    Enthalpy = Energy / mass

    h = E / m

    45 * 10^6 = 320,987.65 / m

    m = 320,987.65 / 45 * 10^6

    m = 7.133 * 10^-3 kg

    m = 7.133 mg

    Also, given that, density is 680kg/m³

    Density is given as

    Density = mass / Volume

    ρ = m / v

    Then, v = m / ρ

    v = 7.133 * 10^-3 / 680

    v = 1.049 * 10^-5 m³

    We know that

    1mL = 10^-6 m³

    Therefore,

    v = 1.049 * 10^-5 m³ * 1mL / 10^-6m³

    v = 10.49 mL
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Neglecting the presence of friction, air drag, and other inefficiencies, how much gasoline is consumed when a 1300 kg automobile ...” in 📘 Engineering if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers