Ask Question
18 April, 03:00

Calculate the rate of heat conduction out of the human body, assuming that the core internal temperature is 37.0°C, the skin temperature is 34.8°C, the thickness of the tissues between averages 1.00 cm, and the surface area is 1.75 m2. The conductivity of tissue is 0.20 J / (s · m · °C).

+1
Answers (1)
  1. 18 April, 05:53
    0
    The answer is 105 W

    Explanation:

    Solution

    Given that:

    The core temperature is = 37.0°C

    The skin temperature is = 34.8°C,

    The thickness of the tissues is on the average of = 1.00 cm

    The surface area = 1.75 m²

    The conductivity of tissue is = 0.20 J (s. m. °C)

    Now,

    The rate of heat transfer through a means of conduction of materials is represented as follows:

    Q / t = kA (T₂ - T₁) / d

    Where

    k = the thermal conductivity

    A = denoted as the surface area

    d = the thickness

    (T₂ - T₁) = is the temperature difference of the body

    Thus

    Q/t = kA (T₂ - T₁) / d

    We now substitute the values of 1.75 m² for A, 0.20 J / (s. m. °C) for k, 37.0°C, for T₁, 34.8°C for T₂, 1.00 cm for d

    We have the following inputs:

    Q/t = (0.20 J/s. m. °C) (1.75 m²) (37.0°C - 34.8°C) / ((1 cm) (10^⁻2/1 cm))

    Now

    Q/t = (0.20 J/s. m. °C) (1.75 m²) (3.00 ° C) / (0.01 m)

    Q/t = 1.05 / (0.01)

    Q/t = 105 J/s

    Therefore, the rate of heat conduction is 105 W
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Calculate the rate of heat conduction out of the human body, assuming that the core internal temperature is 37.0°C, the skin temperature is ...” in 📘 Engineering if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers