Ask Question
11 January, 14:50

Part A A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psi. It had a wall thickness of 0.25 inches and an inner diameter of 8 inches. Use Mohr's Circle to determine the absolute maximum shear stress in the pressure vessel when it is subjected to this pressure. A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure,. It had a wall thickness of 0.25 inches and an inner diameter of 8 inches. Use Mohr's Circle to determine the absolute maximum shear stress in the pressure vessel when it is subjected to this pressure. 1200 psi 900 psi 600 psi 300 psi

+2
Answers (2)
  1. 11 January, 16:25
    0
    Answer: 600 psi

    Explanation:

    Hoop stress is the circumferential force per unit areas (Psi) in the pipe wall due to internal pressure. It can be regarded to as the largest tensile stress in a supported pipe carrying a fluid under pressure. Trenchless methods are used to replace pipes that have failed or correct system issues such as clogs or blockages that inhibits internal flow.

    Firstly, calculate the hoop stress in the pressure vessel which is given as:

    σh = pd/2t

    Where,

    Internal pressure gauge (P) = 75psi

    Inner diameter (d) = 8inches

    Wall thickness = 0.25 inches

    With the above, σh is given as:

    σh = 75 * 8 / 2 * 0.25

    σh = 600/0.5

    σh=1200 psi

    Next, the longitudinal stress in the pressure is calculated. This is given as:

    σi = pd/4t

    σi = 75 x 8/4 * 0.25

    σi = 600psi/1

    σi = 600psi

    The maximum shear stress is the maximum concentrated shear force in a small area.

    It is very critical for structural engineers to locate and evaluate the maximum shear stress in a member in order to design.

    After this, the Mohr circle is used to calculate the average maximum stress in the pressure vessel which is given as follows:

    Tmax=σh/2

    Tmax = 1200/2

    Tmax = 600psi.

    In conclusion, the maximum shear stress in the pressure vessel is 600psi
  2. 11 January, 16:27
    0
    rmax = 600psi

    Explanation:

    Hoop stress=pd/2t=75x8/2*0.25=1200psi

    Now the longitudinal stress = pd/4t=75x8/4x0.25=600psi

    Now the absolute max. Shear stress = 1200/2 = 600psi
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Part A A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psi. It had a wall thickness of 0.25 ...” in 📘 Engineering if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers