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6 March, 01:26

Determine the total condensation rate of water vapor onto the front surface of a vertical plate that is 10 mm high and 1 m in the horizontal direction. The plate is exposed to saturated steam at atmospheric pressure and is maintained at 75oC.

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Answers (2)
  1. 6 March, 02:02
    0
    Q = 63,827.5 W

    Explanation:

    Given:-

    - The dimensions of plate A = (10 mm x 1 m)

    - The fluid comes at T_sat, 1 atm.

    - The surface temperature, T_s = 75°C

    Find:-

    Determine the total condensation rate of water vapor onto the front surface of a vertical plate

    Solution:-

    - Assuming drop-wise condensation the heat transfer coefficient for water is given by Griffith's empirical relation for T_sat = 100°C.

    h = 255,310 W / m^2. K

    - The rate of condensation (Q) is given by Newton's cooling law:

    Q = h*As * (T_sat - Ts)

    Q = (255,310) * (0.01*1) * (100 - 75)

    Q = 63,827.5 W
  2. 6 March, 04:46
    0
    Q = 63,827.5 W

    Explanation:

    From the questions given, we recall the following,

    The dimensions of vertical plate A = (10 mm x 1 m)

    The fluid comes at T_sat, 1 atm.

    The surface temperature pressure maintained T_s = 75°C

    Thus we determine,

    The total rate of condensation of water vapor onto the front surface of a vertical plate

    Assuming drop-wise condensation the heat transfer coefficient for water is given by

    Griffith's empirical relation for T_sat = 100°C.

    Then

    h = 255,310 W / m^2. K

    The rate of condensation (Q) is stated by Newton's cooling law:

    Q = h x As x (T_sat - Ts)

    Q = (255,310) x (0.01 x 1) x (100 - 75)

    Therefore

    Q = 63,827.5 W
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