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18 June, 10:29

A rectangular beam is 14 in. wide and has an effective depth of 20.5 in. The beam contains No. 3 (No. 10) stirrups spaced at 9 in. For f c = 3000 psi and f yt = 60,000 psi, calculate the nominal shear capacity of the section.

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  1. 18 June, 11:43
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    the nominal shear capacity of the section.=61505. 94ibor

    61.51k

    Explanation:

    given that

    beam width = 14 in

    effective depth = 20.5 in

    fc = 3000psi

    fyt = 60,000 psi

    norminal share capacity vn = vc + vs

    vc = 2d√ft bd

    = 2 x1 x √3000 x14 x 20.5

    =31439.27

    vs = Avt + fytd/s

    = 2 x 0.11 x 60,000 x 20.5/9

    = 30066.67ib

    therefore

    vn = vc + vs

    = 31439.27 + 30066.67

    = 61505. 94ib

    or

    61.51k
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