A sample of an unknown substance has a mass of 0.465 kg. If 3,000.0 J of heat is required to heat the substance from 50.0°C to 100.0°C, what is the specific heat of the substance?

Use q equals m C subscript p Delta T ...

0.00775 J / (gi°C)

0.0600 J / (gi°C)

0.129 J / (gi°C)

0.155 J / (gi°C)

Question

English

Harley Boyd

9 January, 06:25

A sample of an unknown substance has a mass of 0.465 kg. If 3,000.0 J of heat is required to heat the substance from 50.0°C to 100.0°C, what is the specific heat of the substance?

Use q equals m C subscript p Delta T ...

0.00775 J / (gi°C)

0.0600 J / (gi°C)

0.129 J / (gi°C)

0.155 J / (gi°C)

+5

Answers (2)

Know the Answer?

Avery · Answer 1

Answer: 0.129J (gioc)

Explanation:

The basic formula for specific heat is Q=MC∆t, where m is the mass, C is the specific heat, and ∆t is the change in temperature.

The parameters given are Q = 3000j = 3kj, mass is 0.465 and ∆t is (100-50) = T2-T1

By imputing them we have;

Q=MC∆T

30 = 0.465xCx (100-50)

3=23.25C

C = 3/23.25

=0.129J (gioC

A sample of an unknown substance has a mass of 0.465 kg. If 3,000.0 J of heat is required to heat the substance from 50.0°C to 100.0°C, what is the specific heat of the substance?Use q equals m C subscript p Delta T ...0.00775 J / (gi°C)0.0600 J / (gi°C)0.129 J / (gi°C)0.155 J / (gi°C)