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16 July, 15:36

Draw the alkene formed when 1-heptyne is treated with one equivalent of hbr.

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  1. 16 July, 18:23
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    1-heptyne is a compound which consists of 7 carbons with a triple bond between the first and second C. When this reacts with HX (X being a halogen), it follows the Markovnikov Rule. This means that the hydrogen bonds with the carbon containing a lot of bonding hydrogen atoms. At the same time, the halogen bonds with the carbon with the least H atoms.

    Thus, the product would be

    2-bromo-1-heptene
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