The first aircraft has 85 more seats than the second aircraft. the third aircraft has 51 fewer seats than the second aircraft. if their a total of seats is 436, find the number of seats of each aircraft

Lets start with the 2nd flight.

Number of seats on the 2nd plane: X

Number of seats on the 1st plane : X+85

Number of seats on the 3rd plane: X-51

Total number of seats = 436.

436 = (x) + (x+85) + (x-51)

436 = 3x+34

436-34=3x

402=3x

402/3=x = 134 - on 2nd plane.

134+85 = 219 on 1st plane.

134-51 = 83 on the 3rd plane.

Quick Check

134+219+83 = 436

436=436! So, our answer is correct!