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17 October, 11:07

The ocean is not flat, since the earth is curved. how many meters lower will its surface be 50.0 km from the ship along a horizontal line parallel to the surface at the ship

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  1. 17 October, 12:45
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    To go the maximum distance the shell must be fired at an angle of 45 degrees, which means its initial horizontal and vertical velocities are equal; call it v_1. From y=y_0 + v_1 t - (1/2) gt^2 you can set up an equation for the time the shell is aloft. Then use that expression for time in the equation for horizontal motion: x = x_0+v_1 t = 41Km and solve for v_1. Don; t forget that the initial velocity is the vector sum of the initial vertical and horizontal velocity components.

    Once you have the answer to (a), (b) should be straight forward.
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