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27 December, 17:55

A compound used to test for the presence of ozone in the stratosphere contains 96.2 percent thallium and 3.77 percent oxygen what is its empirical formula?

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  1. 27 December, 21:50
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    When ozone = O3. and we have 96.2% thallium of the compound. and 3.77% oxygen of the compound. We need to get the no. of moles of thallium & oxygen to get the empirical formula.

    So we can assume that:

    96.2% thallium = 96.2 grams of thallium

    3.77% oxygen = 3.77 grams of oxygen

    as each 100 gram of the compound contains 3.77 grams of O2 & 96.2 grams of Ti

    no. of moles of thallium = 96.2 gm/molar mass of thallium

    = 96.2 gm / 204 = 0.5 mol

    no. of moles of oxygen = 3.77 gm / molar mass of oxygen

    = 3.77 gm / 16

    = 0.25 mol

    to get the empirical formula we need to make this numbers a whole numbers so we multiply by 4 by oxygen and thallium to get the lowest whole numbers that we can get.

    So, after multiple:

    ∴ no. of moles of oxygen = 1

    and no. of moles of thallium = 2

    So the empirical formula is

    Ti2O1



    Ti2O
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