Ask Question
30 March, 05:14

Thermal emissions by solid bodies can be analyzed to provide information on the temperature at a few wavelengths below the surface. Observations of the night hemisphere of Mercury longward of ∼10 cm yield temperatures close to the diurnal equilibrium temperature. As the radiation is obviously able to escape directly from the regions being observed, why does it not get much colder than this during the long mercurian night?

+3
Answers (1)
  1. 30 March, 06:53
    0
    Answer:T = 2898*10^-5K

    Explanation:

    wavelength = 10cm

    Using Wien's Law

    maximum wavelength = 2898*10^-6/temp (K)

    thus T=2898*10^-6/10*10^-2

    T = 2898*10^-5K

    this is the maximum observed temperature of 10 cm wavelength black body

    since this temperature is close to the diurnal equilibrium temperature, that's why it not get much colder.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Thermal emissions by solid bodies can be analyzed to provide information on the temperature at a few wavelengths below the surface. ...” in 📘 Geography if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers