A basket has a mass of 5.5 kg. Find the magnitude of the normal force if the basket is at rest on a ramp inclined above the horizontal at:

a) 0 degrees (horizontal surface)

b) 12 degrees

c) 25 degrees

d) 45 degrees

The free body diagram consists of:

1) Weight force, which is a vertical arrow downward

2) A Normal force that is perpendicular to the ramp.

The Normal force can be decomposed in a vertical component and an horizontal component.

The vertical component, Ny, must equal the weight force, due to equilibrium (rest) condiition = >

Ny = weight = m*g = 5.5kg*9.8m/s^2 = 53.9 N

By geometry the vertical component of the Normal force, Ny is such that

cos (angle) = N / Ny = > N = Ny * cos (angle)

=> N = 53.9N * cos (angle)

Now use that equation for each option:

a) 0 ° = > N = 53.9N * cos (0) = 53.9N

b) 12° = > N = 53.9 * cos (12) = 52.7N

c) 25° = > N = 53.9 * cos (25) = 48.9N

d) 45° = > N = 53.9 * cos (45) = 38.1N