What is the least perimeter of a rectangle with an area of 32square. ft

Ok so least perimiter

area=legnth timew width

32=area

32=LW

from experience, I know that the closer L is to W, the smaller the perimiter

so set L=W (this makes it a square and this is allowed since a square is a rectangle)

32=L^2=W^2

take square root

√32=L=W

4√2=L

perimiter=2L+2W

L=W

perimiter=2L+2L

p=4L

L=4√2

p=4 (4√2)

P=16√2

aprox

22.63 ft

so the answer is

16√2 ft or 22.63 ft

The factors are 2,16,1,32,4 and 8. If it was 2 by 16, the perimeter would be 36. If it was 1 by 32, the perimeter would be 66. If it was 4 by 8, the perimeter would be 24. The smallest number is 24 so the smallest the perimeter could be is 24cm.