Part A: Factor 5x2a2 - 19xa2 - 4a2. Show your work. Part B: Factor x2 + 14x + 49. Show your work. Part C: Factor x2 - 100. Show your work.

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Colby Lee

17 June, 02:10

Part A: Factor 5x2a2 - 19xa2 - 4a2. Show your work. Part B: Factor x2 + 14x + 49. Show your work. Part C: Factor x2 - 100. Show your work.

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Hayden Flores · Answer 1

Part A: First, we factor out a^2 to obtain: a^2 [5x^2 - 19x - 4] = a^2[ (5x+1) (x-4) ] Part B: By inspection, we can use the factors (x+7) (x+7). To check that we have indeed chosen correctly, we will multiply our factors to obtain x^2 + 7x + 7x + 49 = x^2 + 14x + 49 = 0, which is correct. Part C: Again, we can use trial and error and try the factors (x+10) (x-10). Multiplying throughout, we obtain x^2 + 10x - 10x - 100 = x^2 - 100.