What is the hydrate formula for something that is 0.0248 mol Bal2 and 0.075 mol H20?

Answer: BaI {2} ⋅ 4 H {2} O

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Explanation: The idea here is that you need to use the number of moles of anhydrous barium iodide, BaI {2}, and of water, H {2} O, to find the mole ratio that exists between the anhydrous salt and its water of hydration in the hydrate.