What is the solution to this system of equations?

x+2y=4

2x-2y=5

A) (3, Negative 5 and one-half)

B) (3, one-half)

C) no solution

D) infinitely many solutions

Answer: B

Explanation: x+2y=4 equ①

2x-2y=5 equ②

Add:equ①+②

3x = 9

x = 3

Substitute x=3 in equ ①

3+2y=4

2y = 1

y = 1/2

The answer would be B (3, one-half)

Explanation:

If you add the two equations together, the + 2y and - 2y cancel out, leaving 3x=9.

So, we know that x is three (9/3=3)

Substitute x as 3 in either equation (I used the first)

3+2y=4

2y=1

y = 1/2

So, x is 3 and y is one-half, making the answer B