John bikes 22 km per hour and starts at mile 10. Gwyn bikes 28 km per hour and starts at mile 0. Which system of linear equations represents this situation?

Example answer (not right)

A. John d=22t+

Gwym: d = 28t

answer is:

John: d=22t+10

Gwyn: d=28t

If j is the distance in km John reaches after time t hours, and g is the same for Gwynn, the equations are

j=10+22t and g=28t.

If x is the distance at which they meet the equations form a system from which t, when they meet, can be calculated: 10+22t=28t, 6t=10, t=5/3=1 hour 40 minutes. And they meet at 28*5/3=10+22*5/3=46.67km.