6) Jimmy's school is selling tickets to a play. On the first day of ticket sales the school sold 6 adult

tickets and 8 child tickets for a total of $50. The school took in $53 on the second day by selling

7 adult tickets and 8 child tickets. Find the price of an adult ticket and the price of a child ticket.

Let "x" be the cost of an adult ticket

let "y" be the cost of a child ticket

1st day: 50=6x+8y

2nd day: 53=7x+8y

Let both equations equal 0

0=6x+8y-50

0=7x+8y-53

Let equation 1 = equation 2

6x+8y-50=7x+8y-53

Isolate x

7x-6x=53-50+8y-8y

x=3

substitute x=3 into equation 1

6 (3) + 8y=50

y=4

Therefore the cost of a child ticket is $3 and the cost of an adult ticket is $4