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3 December, 15:03

A girl is out jogging at 1.75 m/s and accelerates at 3.29 m/s2 over a displacement of 295 m. What is the girl's final velocity

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  1. 3 December, 17:00
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    Answer;

    = 44.093 m/s

    Explanation;

    Using the equation;

    v² = u² + 2as; where v is the final velocity, u is the initial velocity, s is the displacement and a is the acceleration.

    v² = 1.75² + 2 * 3.29 * 295

    v² = 1944.1625

    v = sqrt 1944.1625

    v = 44.093 m/s

    The girl's final velocity is 44.093 m/s
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